15 lines
327 B
Python
15 lines
327 B
Python
# Среднеквадратичное отклонение sd
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list_data = [int(value) for value in input().split()]
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n = len(list_data)
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Sum = 0
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for value in list_data:
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Sum += value
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SUm=Sum/n
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Sum = 0
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for value in list_data:
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a = (value - SUm)**2
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Sum += a
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D = (Sum / (n - 1 ))
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sd = D ** 0.5
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print (sd)
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